Question

What point on the y axis is at the distance of 10 units from the point (8,8)

Answer 1

Answer:

So, the required point on y-axis is (0, 2) and (0, 14)

Step-by-step explanation:

Let P(0, y) be the required point on y-axis.

Given, distance between the points (0, y) and (8, 8) is 10

=> √{(8 - 0)2 + (8 - y)2 } = 10

=> √{64 + (8 - y)2 } = 10

Squaring on both side, we get

64 + (8 - y)2 = (10)2

=> 64 + 64 + y2 - 16y = 100

=> 128 + y2 - 16y = 100

=> y2 - 16y + 128 - 100 = 0

=> y2 - 16y + 28 = 0

=> y2 - 14y - 2x + 28 = 0

=> y(y - 14) - 2(x - 14) = 0

=> ( y - 14) * (y - 2) = 0

=> y = 2, 14

So, the required point on y-axis is (0, 2) and (0, 14)