Question

what point on x-axis is equidistant from the point A(7,6)and B(-3,4)

Answer 1

Answer:

Step-by-step explanation:

let a point on x axis p(x,0) and q(7,6)and r(-3,4)

therefore

      pq=pr

or,   (x-7)^2+(0-6)^2=(x-*-3)^2+(0-4)^2

or,    x^2-14x+49+36=x^2+6x+9+16

or,  -20x+85=25

or,  -20x=-60

or,  x=3 

therefore, p(3,0)

Answer 2

Answer:

To solve this problem we will use the mid-point formula.