Question

what point on x axis is equidistant from the points A(7,6) and B(-3,4) ?

Answer 1

let p be the point which is equidistant frm da pnts given
p(k,0)
Ap = Bp
√(k-7)^2+(6)^2 =√(k+3)^2 + 4^2
k=3

Answer 2

Any point on x-axis is represented by P (x, 0).  where x is a real number.

Distance AP = √[(7-x)²+(6-0)²]   
Distance BP = √[(-3-x)²+(4-0)²]

if they are equal, then : 49+x²-14x + 36 = 9+x²+6x+16
                         20 x = 60
                         => x = 3
   (3, 0) is the point.