Question

what point (or points) on the y axis or at a diatance of 10 units form the points (8, 8) ​

Answer 1

Answer:

Let the points on the y−axis be (0,y).

And the distance from the point (8,8)=10 units

We know that the distance formula

=

(x

2

−x

1

)

2

+(y

2

−y

1

)

2

10=

(8−0)

2

+(8−y)

2

100=64+(8−y)

2

64+y

2

−16y=36

y

2

−16y+28=0

(y−14)(y−2)=0

y=2,14

Hence, the points are (0,2) and (0,14).

Hence, this is the answer.

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Answer 2

Answer:

The points are (0,2) and (0,14).

Step-by-step explanation:

Let the points on the y−axis be (0,y).

And the distance from the point (8,8)=10 units

We know that the distance formula

= $\sqrt{(x_{2}- x_{1})^2 + (y_{2}- y_{1})^2 }$

10 = $\sqrt{(8-0)^2 + (8-y)^2$

100 = 64 + $( 8 - y )^2$

64 + $y^2$ - 16y = 36

$y^2$ - 16y + 28 = 0

(y − 14) (y − 2) = 0

y = 2, 14

Hence, the points are (0,2) and (0,14).