Question

What points on the x-axis are at a distance of 10 units from (-10, -6) ?

Answer 1

Answer:

(-18,0)  &  (-2,0).

Step-by-step explanation:

Let the required point on x-axis be (x,0).

Applying distance formula ,    $10=\sqrt{(x+10)^{2}+(0+6)^{2} }$

                  =>   $100= x^{2} +100 + 20x +36$

                  =>   $x^{2}+20x+36=0$

                  =>   x = -10 ± 8

                  =>   x = -18,-2.

Therfore, the required points are: (-18,0) and (-2,0).