Question

what potential energy is acquired by a hammer with a mass of 0.75 kg when raised 0.35 m?need proper solution​

Answer 1

Answer:-

$\red{\bigstar}$ Potential energy $\large\leadsto\boxed{\rm\pink{2.57 \: J}}$

• Given:-

• Mass of the hammer = 0.75 kg

• Height to which hammer is raised =0.35 m

• To Find:-

• Potential energy acquired by the hammer.

• Solution:-

We know,

$\pink{\bigstar}$ $\large\underline{\boxed{\bf\green{P.E = mgh}}}$

where,

• P.E = potential energy

• m = mass of the body

• g = acceleration due to gravity

• h = height of the body

★ Taking acceleration due to gravity [g] as 9.8 m/s².

• Substituting in the Formula:-

→ $\sf P.E = 0.75 \: kg \times 9.8 \: ms^{-2} \times 0.35 \: m$

→ $\sf P.E = 7.35 \: kg.m.s^{-2} \times 0.35m$

→ $\sf P.E = 2.5725 \: kg.m^2.s^{-2}$

→ $\sf P.E = 2.5725 \: J$

★ $\large{\tt\red{P.E = 2.57 \: J}}$

Therefore, the potential energy acquired by the hammer is 2.57 J.

Answer 2

Answer:

Answer:-

\red{\bigstar}★ Potential energy \large\leadsto\boxed{\rm\pink{2.57 \: J}}⇝

2.57J

• Given:-

Mass of the hammer = 0.75 kg

Height to which hammer is raised =0.35 m

• To Find:-

Potential energy acquired by the hammer.

• Solution:-

We know,

\pink{\bigstar}★ \large\underline{\boxed{\bf\green{P.E = mgh}}}

P.E=mgh

where,

P.E = potential energy

m = mass of the body

g = acceleration due to gravity

h = height of the body

★ Taking acceleration due to gravity [g] as 9.8 m/s².

• Substituting in the Formula:-

→ \begin{gathered}\sf P.E = 0.75 \: kg \times 9.8 \: ms^{-2} \times 0.35 \: m \\ \end{gathered}

P.E=0.75kg×9.8ms

−2

×0.35m

→ \begin{gathered}\sf P.E = 7.35 \: kg.m.s^{-2} \times 0.35m \\ \end{gathered}

P.E=7.35kg.m.s

−2

×0.35m

→ \begin{gathered}\sf P.E = 2.5725 \: kg.m^2.s^{-2} \\ \end{gathered}

P.E=2.5725kg.m

2

.s

−2

→ \begin{gathered}\sf P.E = 2.5725 \: J \\ \end{gathered}

P.E=2.5725J

★ \large{\tt\red{P.E = 2.57 \: J}}P.E=2.57J

Therefore, the potential energy acquired by the hammer is 2.57 J.