Question

What power is needed to lift a 49kg person a vertical distance of 5.0m in 20.0s?
(125W (B) 210 W (C) 120 W
(D) 25 W​

Answer 1

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Power=Work/time

Work=Force*Distance (in our case)

Force=m*g (lifting force is equal to weight of the body)

Given,

m = 49kg

Distance = 5m

time = 20s

g = 9.8 m/ sec²

Force=m*g

= 49 * 9.8

= 480.2 N

Work = Force * distance

= 480.2 * 5

= 2401 J

Power = Work / time

= 2401 / 20

=120.05 Watt

Power=120 Watt ( approx.)

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Answer 2

Answer:

120 wwwwwwwwwwwwwwwww