Question

What pressure is required to compress 196.0 liters of air at 1.00 atmosphere into a cylinder whose volume is 26.0 liters?

Answer 1

is constant at a constant temperature.

if volume of the gas increases, its pressure decreases, and vice versa. mathematically, if the volume of the gas is

V

1

and its pressure is

P

1

. Let us suppose that its volume has been increased to

V

2

, the as per the Boyle's law its pressure will decrease and let us assume the new pressure is

P

2

.

P

1

V

1

=

P

2

V

2

P

1

= 1 atm

V

1

= 196 L

P

2

= ?

V

2

= 26 L substitute the values;

1 atm x 196 L =

P

2

x 26 L

P

2

= 1 atm x 196 L / 26 L

P

2

= 196 atm L / 26 L = 7.53 atm

Answer 2

Answer:

P2=7.53bar

Explanation:

concept - using boyle's law

given - P1= 196.0L

V1 = 1.00bar

V2= 26.0L

find - P2=?

explanation

P1V1=P2V2

196*1=26*P2

P2= 196/26

P2=7.53bar

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