Question

what pressure is required to reduce the volume of a lead block by 1% ? [ Bulk modulus of lead block is 6 into 10 raised to 9 N/m square​]

Answer 1

Answer:  6×$10^{7} N/m^{2}$

Explanation:

pressure intensity=Bulk modulus * volumetric strain

k=bulk modulus=6×$10^{9}$

volumetric strain=$10^{-2}$

∴pressure =6×$10^{9}$×$10^{-2}$

pressure=6×$10^{7}$N/$m^{2}$