What pressure should be applied to a lead block to
reduce its volume by 10% ?
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Answered by
1
Alright!
We were told that the compression is ten percent. Or, in other words.
1−V2V1=.1
V2V1=.9
Assuming that bulk modulus is constant.
ΔP=−KlnV2V1
K=ΔPlnV1V2
Alternatively, the engineering strain could be used instead of true strain, which would just be…
K=ΔP1−V2V1
There you go
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