Question

What pressure should be applied to a lead block to

reduce its volume by 10% ?

(Bulk modulus of lead = 6 10 N / m

9 2 ).​

Answer 1

Explanation:

Given What pressure should be applied to a lead block to reduce its volume by 10% ?

• Volumetric strain = 10% = 10 x 10^-2
• Bulk modulus of elasticity = 6 x 10^9 N/m^2
• To find pressure intensity
• We know that Bulk modulus of elasticity = k = volumetric stress / volumetric strain
• Therefore volumetric stress = K x Volumetric strain
• Also Pressure intensity = K x volumetric strain
•                                       = 6 x 10^9 x 10 x 10^-2

Therefore pressure intensity will be 6 x 10^8 N / m^2  

Reference link will be

https://brainly.in/question/14683381

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