Question

what pressure should be applied to a lead block to reduce it's volume by 20% ? bulk modulus of lead =6×10^9 N/m^2.​

Answer 1

Answer:

Volumetric strain = 10% = 10 x 10^-2

Bulk modulus of elasticity = 6 x 10^9 N/m^2

To find pressure intensity

We know that Bulk modulus of elasticity = k = volumetric stress / volumetric strain

Therefore volumetric stress = K x Volumetric strain

Also Pressure intensity = K x volumetric strain

                                     = 6 x 10^9 x 10 x 10^-2

Therefore pressure intensity will be 6 x 10^8 N / m^2  

hope it helps

tq,./

Explanation: