Question

What pressure will be exerted by a 10 N box that has equal sides of 1 meter (hint: area of square is given by a², where 'a' is the side of the square)
a) 1 Pa

b) 10 Pa

c) 20 Pa

d) 2 Pa

Answer 1

Answer:

Option B (10 Pa)

Explanation:

As per the provided information in the given question, we have :

• Force applied by box (F) = 10 N
• Length of the side of the box = 1 m

We are asked to calculate the pressure exerted by the box.

As we know that,

$\longmapsto \bf {P = \dfrac{F}{A} }$

• P denotes pressure
• F denotes force
• A denotes area

Now, in order to calculate the pressure exerted, we need to calculate the area in contact first. As the box has equal sides, that means we need to apply the area of square formula.

$\longmapsto \rm {Area_{(Square)} = (Side)^2}$

$\longmapsto \rm {Area_{(Box)} = (1 \; m)^2}$

$\longmapsto \bf {Area_{(Box)} = 1 \; m^2}$

Now, substituting the values in the formula of pressure.

$\longmapsto \rm {P = \dfrac{10 \; N}{1 \; m^2} }$

$\longmapsto \rm {P = 10\; N.m^{-2}}$

$\longmapsto \bf {P = 10\; Pa}$

∴ Pressure exerted by the box is 10 Pa.

$\rule{200}2$

Explore More!!

• Pressure is defined as force per unit area.
• SI unit of pressure is Pascal.
• Pascal is denoted by 'Pa'.
• Pa is equivalent to 1 N/m².
• When area is less, pressure is more.
• When area is more, pressure is less.
• When force is more, pressure is more.

Answer 2

Answer:-

Firstly find area of box

• Side=1m

$\\ \sf \longmapsto Area=(side)^2$

$\\ \sf \longmapsto Area=(1)^2$

$\\ \sf \longmapsto Area=1m^2$

• Force=10N

We know that

$\boxed{\sf Pressure=\dfrac{Force}{Area}}$

$\\ \sf \longmapsto Pressure=\dfrac{10}{1}$

$\\ \sf \longmapsto Pressure=10N/m^2$

$\\ \sf \longmapsto Pressure=10Pa$

Note:-

SI units :-

• Pressure=Pascal(Pa)
• Force=Newton(N)
• Area=sq.m