Chemistry, asked by kay24, 7 months ago

what pressure would be required to compress 2500litre of gas at 1 atm to a vol of 35.5 litre shown in kPa

Answers

Answered by Anonymous
1

Answer:

Given: Volume,V1= 2500litre

V2= 35.5 litre

(1atm= 10Pa)

Pressure,P1 = 10Pa

To find: P2= ?

Solution: P1*V1= P2*V2

10*2500= P2*35.5

Therefore,P2= 70.42*10Pa = 7042Kpa

Answer: 7042KPa.

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