what pressure would be required to compress 2500litre of gas at 1 atm to a vol of 35.5 litre shown in kPa
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Answer:
Given: Volume,V1= 2500litre
V2= 35.5 litre
(1atm= 10⁵Pa)
Pressure,P1 = 10⁵Pa
To find: P2= ?
Solution: P1*V1= P2*V2
10⁵*2500= P2*35.5
Therefore,P2= 70.42*10⁵Pa = 7042Kpa
Answer: 7042KPa.
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