Question

What principal amount to rs16000 in 6years at 10% simple interest

Answer 1

Given:-

• Amount, A = Rs 16000

• Time = 6 years

• Rate = 10% p.a

To find out:

Find the Principal?

Formula used:

• S.I = P × R × T / 100

Solution:

Let the principal be Rs x.

SI = P×R×T/100

SI = x × 10 × 6/100

SI = 6x/10

SI = 3x/5

Now,

Amount = Principal + SI

⇒16000 = x + 3x/5

⇒16000 = 5x+3x/5

⇒16000 = 8x/5

⇒8x = 16000×5

⇒x = 16000×5/8

⇒x =80000/8

⇒x = Rs. 10000

Hence, Principal, P is Rs. 10,000

Answer 2

↪Question :-

• What principal amount to Rs 16000 in 6 years at 10% simple interest.

↪Solution :-

Given:

• Amount (A) = Rs 16000
• Time (T) = 6 years
• Rate (R) = 10%

To Find :

• The principal amount.

Let the principal be Rs x.

$\boxed {\tt{\bigstar{SI=\dfrac{P\times R\times T}{100}}}}$

$\sf{ : \implies {SI= \dfrac{P\times R\times T}{100}}} \\ \\ \sf{ : \implies {SI= Rs \: (\dfrac{x\times 10\times 6}{100})}} \\ \\ \sf{ : \implies {SI=Rs \: \dfrac{3x}{5} }}$

$\boxed {\tt{\bigstar{A=P+SI}}}$

$\sf{ : \implies {A=P+SI}} \\ \\ \sf{ : \implies {16000=x + \dfrac{3x}{5} }} \\ \\ \sf{ : \implies {16000= \dfrac{5x + 3x}{5} }} \\ \\ \sf{ : \implies {16000= \dfrac{8x}{5} }} \\ \\ \sf{ : \implies {16000 \times 5=8x}} \\ \\ \sf{ : \implies { \dfrac{16000 \times 5}{8}=x}} \\ \\ \sf{ : \implies { 2000 \times 5=x}} \\ \\ \sf{ : \implies { 10000 =x}} \\ \\ \sf{ : \implies {x = 10000 }}$

$\bf {\therefore{The\:principal \:amount\:is\:Rs \:10000.}}$

$\rule {307}{2}$