What principal will earn interest of 812 at 3by 1/2%
per annum in 7 by 1/4 years?
Answers
Answer:
sorry I didn't know the answer
Answer:
Rs 3200. is the answer
Step-by-step explanation:
\mathsf{\tiny{\red{Interest = Rs \: \: 812}}}Interest=Rs812
\begin{gathered}\mathsf{\tiny{\red{Rate = 3 \frac{1}{2} \% = \frac{7}{2} \% \: \: p.a.}}} \\ \end{gathered}Rate=321%=27%p.a.
\begin{gathered}\mathsf{\tiny{\red{Time = 7 \frac{1}{4} = \frac{29}{4} \: \: years}}}\\ \end{gathered}Time=741=429years
\mathsf{Let \: \: the \: \: sum \: \: be \: \: Rs \: \: P.}LetthesumbeRsP.
\mathsf{\tiny{\blue{We \: \: know \: \: that}}}Weknowthat
\begin{gathered}\mathsf{\tiny{\green{I = \frac{P \times R \times T}{100}}}} \\ \end{gathered}I=100P×R×T
\begin{gathered}\mathsf{\tiny{\green{ = > 812 = \frac{P \times 7 \times 29}{100 \times 2 \times 4 }}}} \\ \end{gathered}=>812=100×2×4P×7×29
\begin{gathered} \mathsf{\tiny{\green{= > 812 = \frac{203P}{800}}}} \\ \end{gathered}=>812=800203P
\begin{gathered}\mathsf{\tiny{\green{ = > 203P= 812 \times 800 }}} \\ \end{gathered}=>203P=812×800
\begin{gathered}\mathsf{\tiny{\green{ = > P = \frac{812 \times 800}{203}}}} \\ \end{gathered}=>P=203812×800
\mathsf{\tiny{\green{ = > P = 3200}}}=>P=3200
\mathsf\purple{Hence, \: \: the \: \: sum \: \: is \: \: Rs \: \: 3200.}Hence,thesumisRs3200