Question

what quadratic equation have its zero as 1/4and 3/4?​

Answer 1

Answer:

$16x^2 - 16 x + 3$

Step-by-step explanation:

The zeros of a quadratic polynomials are 1/4 and 3/4

The sum of the zeros =∝ + β = 1/4 + 3/4

                                                $=1 + 3 / 4\\\\=4 / 4\\\\=1$

The product of the zeros = Therefore x=1 is only the

root of given equation   ∝ x (β) = 1/4 x 3/4

                                                   = 3/16     ( 1 x 3 / 4 x 4)

∴ The quadratic polynomial be    $K [x^2-(∝ + \beta ) x + ∝\beta ]$

                                                   ( where k = constant ,a = ∝)

$= k [ x^2 - 1 (x) + 3 /16]\\\\=k [x^2 - x + 3/16]\\\\=k[ 16x^2 -16x + 3 / 16]$

we can put different value of k $16x^2 - 16x + 3$

where k = 16, then quadratic polynomial be

Answer 2

achhi chal rahi hai meri study

exam ab 27 date se suru hogi to thoda tention hai