What quantity (in mL) of a 45% acid solution of a
mono-protic strong acid must be mixed with a 20%
solution of the same acid to produce 800 mL of a
29.875% acid solution ? Online 2017 SET (2)
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Question:
What quantity (in ml) of a 45% acid solution of a mono-protic strong acid must be mixed with a 20% solution of the same acid to produce 800 ml of a 29.875% acid solution ?
Solution:
Let volume of 1st solution = Vml
Then, Volume of 2nd solution = (800–V) mL
We know,
Amount of acid in 1st solution + Amount of acid in 2nd solution = Amount of acid in obtained solution.
45V/100 + 20(800-V) / 100 = 29.875(800)/100
On, solving, we obtain the values of V as:
V = 316 ml
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