What quantity of heat will be produced in a coil of resistance 80 ohm if current of 3 ampere is passed through it for 4 seconds?
Answers
Answered by
15
H=I^2Rt
= 3x3x80x4
=2880
= 3x3x80x4
=2880
silu5:
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Answered by
10
H=I^2Rt
R=80ohm
I=3amp
t=4sec
H=9×80×4
H=2880Joules
R=80ohm
I=3amp
t=4sec
H=9×80×4
H=2880Joules
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