Question

what quantity of Potassium iodate is used to prepare 500 ml of 0.05 M potassium iodate

Answer 1

Answer:

dissolve 12 g of kl in enough water to make 500 ml

Explanation:

50+12

62

0.05 solution

Answer 2

The mass of potassium iodate is 5.35 g

We have to find the quantity of potassium iodate is used to prepare 500 mL of 0.05 M potassium iodate.

Concept : Molarity is the number of moles of solute in a litre of solution.

i.e., Molarity = number of moles/volume of solution in L

Here,

• volume of solution = 500mL = 0.5 L
• molarity of potassium iodate = 0.05M

∴ number of moles of potassium iodate = 0.05 × 0.5 = 0.025 mol

molecular mass of potassium iodate = 214 g/mol

∴ mass of potassium iodate = number of moles × molecular weight

= 0.025 × 214 g = 5.35 g

Therefore the mass of potassium iodate is 5.35 g.

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