What quantity of water results from the combustion of a 0.5⋅g mass of dihydrogen gas?
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2H2 + O2 ------> 2H2O
Here H2 is the limiting reactant.
0.5 g of H2 = 0.5/2
= 0.25 mol
For every 2 mole of H2, 2 mole of water is formed.
So, for 0.25 mole of H2, 0.25 mole of H2O will be formed.
Molar mass of H2O = 18 u
Mass of H2O formed = 0.25 x 18
= 4.5 g
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