Math, asked by vishalgarg3316, 9 months ago

What quantity of water should be added to reduce 16 liters of 25% acidic liquid to 20% acidic liquid

Answers

Answered by pvmvbb
3

Answer:

This question is related to Indirect Proportion

 16 X 25 = 20 X x

= 400 = 20x

= x = 400/20

= x =20

20 - 16 = 4

Therefore, 4 litres of water should be added.

Step-by-step explanation:

Answered by kjuli1766
0

Concept

Inverse proportion states that if there is an increase in one it leads to decrease in other one similarly if there is an decrease in one it leads to increase in the other quantity.

For example

Speed is inversely proportional to time

Given

16 litres of 25% acidic liquid

Find

What quantity of water should be added to reduce 16 litres of 25% acidic liquid to 20% acidic liquid

Solution

This question is based on inverse proportion

Let the quantity of water should be added to reduce 16 litres of 25% acidic liquid to 20% acidic liquid be x

So,

16 * (25/100) = (20/100) * x

16 * 25 = 20 * x

x = (16*25)/20

x = 4 * 5

x = 20

The quantity of water should be added to reduce 16 litres of 25% acidic liquid to 20% acidic liquid is 20 litres.

#SPJ2

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