What quantity of water should be added to reduce 16 liters of 25% acidic liquid to 20% acidic liquid
Answers
Answer:
This question is related to Indirect Proportion
16 X 25 = 20 X x
= 400 = 20x
= x = 400/20
= x =20
20 - 16 = 4
Therefore, 4 litres of water should be added.
Step-by-step explanation:
Concept
Inverse proportion states that if there is an increase in one it leads to decrease in other one similarly if there is an decrease in one it leads to increase in the other quantity.
For example
Speed is inversely proportional to time
Given
16 litres of 25% acidic liquid
Find
What quantity of water should be added to reduce 16 litres of 25% acidic liquid to 20% acidic liquid
Solution
This question is based on inverse proportion
Let the quantity of water should be added to reduce 16 litres of 25% acidic liquid to 20% acidic liquid be x
So,
16 * (25/100) = (20/100) * x
16 * 25 = 20 * x
x = (16*25)/20
x = 4 * 5
x = 20
The quantity of water should be added to reduce 16 litres of 25% acidic liquid to 20% acidic liquid is 20 litres.
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