Question

What quantity of water should be added to reduce 5 litres of 45% acidic liquid to 25% acidic liquid?

Answer 1

Answer:

Let x liter of water to be removed

54% of 65 =

100

54

×65=35.1liter of acid

Then

⇒

65−x

35.1

=.78

⇒35.1=.78(65−x)

⇒.78x=50.7−35.1

⇒.78x=15.6

⇒x=20 liters

Answer 2

Answer:

4litres of water should be added to reduce 5 litres of 45% acidic liquid to 25% acidic liquid.

Explanation:

Concept:

Let x amount of water should be added

• To find the amount of acid in 5 litres:

45% of 5 litres= 45/100x5= 2.25 litres

Acid amount is : 2.25litres

To make it 25% acid liquid:

→2.25/5-x= 25/100

→2.25/5-x=0.25

→2.25/0.25=5-x

9=5-x

x= 9-5=4litres

The amount of water added is 4 litres.

FINAL ANSWER: 4litres of water should be added to reduce 5 litres of 45% acidic liquid to 25% acidic liquid.

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