Question

what quantity of water should be added to reduce 6 litres of 50% acidic to 20% acidic water

Answer 1

Answer:

The quantity of water required = 1.8 liters.

Step-by-step explanation:

Given : Water should be added to reduce 6 liters of 50% acidic to 20% acidic water.

To find : What quantity of water is required?

Solution :

6 litres of mixture= 50% acidic

Acidic liquid= 50/100×6= 3liters

Water quantity = 6-3= 3litres

Want only 20% acid = 6×20/100= 6/5liters

Water must be there=(6- 6/5 )litres= 24/5 litre or 4.8 litres

Water must be added= 4.8-3= 1.8litres

Therefore, The quantity of water required = 1.8 liters.

Answer 2

Answer:

Answer is 9 liter

Step by step explanation

according to question,

6×(50/100) = (6+x) × (20/100), because amount of acid remains same, only water is added to reduce the percentage of acid...now solving the above equation 'x' will be,

6×(1/2) = (6+x) ×(1/5)

3= (6+x)x (1/5)

15= (6+x)

x= 15-6= 9 liter