What r the factors of x²-26x+120=0
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Answered by
6
x²-26x+120 = 0
x²-20x-6x + 120=0
x(x-20)-6(x-20) = 0
(x-20)(x-6)=0
x = 20 and 6
the factors are 20 and 6
x²-20x-6x + 120=0
x(x-20)-6(x-20) = 0
(x-20)(x-6)=0
x = 20 and 6
the factors are 20 and 6
Answered by
5
x² - 26x + 120 = 0
x² - 20x - 6x + 120 = 0
x(x-20) - 6(x-20) = 0
(x-20) (x-6) = 0
x - 20 = 0 → x = 20
x - 6 = 0 → x = 6
Therefore,the factors are 20 and 6
Hope it helps
x² - 20x - 6x + 120 = 0
x(x-20) - 6(x-20) = 0
(x-20) (x-6) = 0
x - 20 = 0 → x = 20
x - 6 = 0 → x = 6
Therefore,the factors are 20 and 6
Hope it helps
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