Question

What rate gives ₹ 1,120 as interest on a sum of ₹ 4000 in 2 years?
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Answer 1

Answer:

Dude what kind of math you have?????

Step-by-step explanation:

RULE 1:

Simple Interest (S.I.)= Principal∗Rate∗Time100

or,

S.I.= P∗R∗T100

P= S.I.∗100R∗T, R= S.I.∗100P∗T, T= S.I.∗100P∗R,

RULE 2:

If there are distinct rates of interest for distincttime periods i.e.

Rate for 1st t1 years -> R1%

Rate for 2nd t2 years -> R2%

Rate for 3rd t3 years -> R3%

or,

Then, Total S.I. for 3 years = P(R1T1∗R2T2∗R3T3)100

RULE 3:

If a certain sum becomes ‘n’ times of itself in T years on Simple Interest, then the rate per cent per annum is,

R% = (n−1)Tx100% and

T = (n−1)Rx100%

RULE 4:

If a certain sum becomes n1 times of itself at R1% rate and n2 times of itself at R2% rate, then,

R2 = (n2−1)n1−1xR1 and T2 = (n2−1)n1−1xT1

RULE 5:

If Simple Interest (S.I.) becomes ‘n’ times of principal i.e.

S.I. = P × n then.

RT = n × 100

RULE 6:

If an Amount (A) becomes ‘n’ times of certain sum (P) i.e.

A = Pn then,

RT = (n – 1) × 100

RULE 7:

If the difference between two simple interests is ‘x’ calculated at different annual rates and times, then principal (P) is

P = (x∗100)dr∗dt

where dr = Difference in rate & dt = Difference in time

RULE 8:

If a sum amounts to x1 in t years and then this sum amounts to x2 in t yrs. Then the sum is given by

P = ((da)∗100)(ci)∗time

where da = Difference in amount & ci = Change in time

RULE 9:

If a sum with simple interest rate, amounts to ‘A’ in t1 years and ‘B’ in same t2 years, then,

R% = (B−A)∗100A.t2−B.t1 and

P = A.t2−B.t1t2−t1

RULE 10:

If a sum is to be deposited in equal instalments, then,

Equal instalment = A∗200T[200+(T−1)r]

where T = no. of years, A = amount, r = Rate of Interest.

RULE 11:

To find the rate of interest under current deposit plan,

r = S.I.∗2400n(n+1)∗dA00

where n = no. of months & dA = deposited ammount

RULE 12:

If certain sum P amounts to Rs. A1 in t1 years at rate of R% and the same sum amounts to Rs. A2 in t2 years at same rate of interest R%. Then,

(i) R = A1−A2A2T1−A1T2X100

(ii) P = A2T1−A1T2T1−T2

RULE 13:

The difference between the S.I. for a certain sum P1 deposited for time T1 at R1 rate of interest and another sum P2 deposited for time T2 at R2 rate of interest is

S.I. = P2R2T2−P1R1T1100