Question

What rate gives 1920 as interest on a sum of 64,000 in 2 years?​

Answer 1

$\large \sf {given \: SI = 1920}$

time period T= 2 years

principal amount ,P= ₹64,000

rate of interest R =?

$\huge \sf{SI = \frac{p \times t \times r}{100}}$

$\large \sf ↪r = \frac{si \times 100}{p \times t}$

$\large \bf \frac{1920 \times 100}{64000 \times 2}$

=6%

hence, rate of interest=6