Math, asked by cdhanyatha21, 9 months ago

What rate gives ₹280 as interest on a sum of ₹56,000 in 2 years? ​

Answers

Answered by apurvanshu1905
5

Here Is Your Answer  :-

Principal :- ₹56000

Time :- 2 years

S.I. :- ₹280

Rate  =  (S.I. x 100)/(P x R)

         =  (₹280 x 100)/(₹56000 x 2)

         =  1/4 %

HOPE  IT  IS  HELPFUL

MARK MY ANSWER BRAINLIEST

Answered by prince5132
42

GIVEN :-

  • Principal (P) = Rs.56000
  • Simple Interest (S.I) = Rs. 280
  • Time (T) = 2 years.

TO FIND :-

  • The rate of interest (R)

SOLUTION :-

 \boxed { \bf \:  \implies  R \:  =  \dfrac{ S.I \times 100}{  P \times T } }

 \implies \tt \:  R \:  =   \frac{280 \times 100}{56000 \times  2}  \\  \\  \implies \tt \: R \:  =  \frac{28000}{112000}  \\  \\  \implies \tt R \:  = \frac{28}{112}  \\  \\  \implies \tt \:  \:R = 0.25 \% \: \:  p.a

Hence Rate of Interest (R) = 0.25 %. p.a

ADDITIONAL INFORMATION :-

  \boxed{\begin{minipage}{6cm}  \\  \bf{ \underline{Some Formulae}} \\ \\  \rightarrow  \quad \sf P =  \dfrac{100 \times S.I}{R \times T}  \\  \\  \\  \rightarrow \quad T =  \dfrac{100 \times S.I}{P \times R}  \\  \\  \\  \rightarrow \quad R =  \dfrac{100 \times S.I}{P \times T}  \\  \\  \\  \rightarrow \quad A = P + S.I \\  \\  \\  \rightarrow \quad S.I =  \dfrac{P \times R \times T}{100}  \\  \end{minipage}}

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