Math, asked by solvethemystery2, 4 months ago

What rate gives ₹600 as interest on the sum of ₹10000

in 3 years?​

Answers

Answered by mayajakhar79
0

Solution:-

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❍ Here, the question has given us the S.I, principal and time that are ₹600, ₹10,000 and 3 years respectively. Now, the question has asked us to find out the rate of interest. So, we will apply the formula of Simple Interest to fund the rate of interest.

ANSWER:-

  • The rate of interest is 2%.

GIVEN:-

» Simple Interest = ₹600

» Principal = ₹10,000

» Time = 3 years

TO FIND:-

✰ Rate of interest = ?

FORMULA:-

➛ Simple Interest = P×R×T/100

Where,

  • S.I = Simple Interest
  • P = Principal
  • R = Rate
  • T = Time

SOLVING BY APPLYING THE FORMULA:-

❖ Let the rate be R

↣ 600 = 10,000 × R × 3 / 100

↣ Cancelling the zeros.

↣ 600 = 100 × R × 3 / 1

↣ 600 = 300 × R / 1

↣ 600 × 1 = 300 × R

↣ 600 = 300 × R

↣ 600 / 300 = R

➛ 2 = R

Hence, we got the answer. The rate of interest is 2%.

TO CHECK:-

P = ₹10,000

R = 2%

T = 3 years

⇨ Simple Interest = P × R × T / 100

⇨ S.I = 10,000 × 2 × 3 / 100

⇨ S.I = 10,000 × 6 / 100

⇨ Cancelling the zeros

⇨ S.I = 100 × 6 / 1

⇨ S.I = 100 × 6

⇨ S.I = 600

Hence, checked. The S.I is Rs.600.

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Answered by Anonymous
7

AnswEr-:

  • \boxed{\mathrm {\dag{ Rate \:of\:Interest \:= 2 \%  }}}

Explanation-:

  • \mathrm { Given-:}

  • Simple Interest = Rs. 600.
  • Principal = Rs. 10 ,000.
  • Time = 3 yrs .

  • \mathrm { To\:Find-:}

  • Rate of Interest.

\dag{\mathrm { Solution \:of\:Question \:-:}}

  • \underbrace {\mathrm { Understanding \:The\:Concept \:-:}}

  • We have to find the Rate of Interest when Principal, Simple Interest ( SI) and Times is Given .

  • For this put the known Values in the Formula for Simple Interest . By doing this ,

  • We can get the Rate of Interest.

As , We know that ,

  • \underline{\boxed{\star{\sf{\red{ Simple \:Interest\: = \dfrac{ Principal\times Rate\times Time } {100}.}}}}}

  • Here ,

  • Simple Interest = Rs. 600.
  • Principal = Rs. 10 ,000.
  • Time = 3 yrs .
  • Rate = ??

Now , By Putting known Values in the Formula for Simple Interest-:

  • \longrightarrow {\mathrm { Rs.600 = \dfrac{10000 \times Rate \times 3}{100}}}

  • \longrightarrow {\mathrm { Rs.600 = \dfrac{100\cancel {00} \times Rate \times 3}{\cancel {100}}}}

  • \longrightarrow {\mathrm { Rs.600 = 100 \times Rate \times 3}}

  • \longrightarrow {\mathrm { Rs.600 = 300 \times Rate }}

  • \longrightarrow {\mathrm { \dfrac{600}{300} =  Rate }}

  • \longrightarrow {\mathrm { \dfrac{\cancel {600}}{\cancel {300}} =  Rate }}

  • \longrightarrow {\mathrm { Rate \: = 2 \%  }}

Hence,

  • \boxed{\mathrm {\dag{ Rate \:of\:Interest \:= 2 \%  }}}

________________________________________________________________

\huge{\mathrm { Verification\:-:}}

As , We know that ,

  • \underline{\boxed{\star{\sf{\blue{ Simple \:Interest\: = \dfrac{ Principal\times Rate\times Time } {100}.}}}}}

  • Here ,
  • Simple Interest = Rs. 600.
  • Principal = Rs. 10 ,000.
  • Time = 3 yrs .
  • Rate = 2 %

Now , By Putting known Values in Formula for Simple interest-:

  • \longrightarrow {\mathrm { Rs.600 = \dfrac{10000 \times 2 \times 3}{100}}}

  • \longrightarrow {\mathrm { Rs.600 = \dfrac{100\cancel {00} \times 2 \times 3}{\cancel {100}}}}

  • \longrightarrow {\mathrm { Rs.600 = 100 \times 2 \times 3}}

  • \longrightarrow {\mathrm { Rs.600 = 200 \times 3}}

  • \longrightarrow {\mathrm { Rs.600 = Rs.600 }}

Therefore,

  • \longrightarrow {\mathrm { LHS = RHS }}

  • \longrightarrow {\mathrm { Hence \: Verified! }}

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