Question

what rate gives rupees 840 as interest on a sum of rupees 5600 in 2 years​

Answer 1

Answer:

7.5%

Step-by-step explanation:

int= 840

principal = 5600

t =2yrs

let rate = r

int = PRT / 100

840 = 5600 × 2 × r

100

840 = 112 r

840 = r

112

7.5% = r

Answer 2

Step-by-step explanation:

Solution:

Solution:Here, Principal (P) = Rs. 56,000, Simple Interest (S.I.) = Rs. 280, Time (T) = 2 years

Solution:Here, Principal (P) = Rs. 56,000, Simple Interest (S.I.) = Rs. 280, Time (T) = 2 yearsSimple Interest = \frac{P\times R\times T}{100}

Solution:Here, Principal (P) = Rs. 56,000, Simple Interest (S.I.) = Rs. 280, Time (T) = 2 yearsSimple Interest = \frac{P\times R\times T}{100} 100

Solution:Here, Principal (P) = Rs. 56,000, Simple Interest (S.I.) = Rs. 280, Time (T) = 2 yearsSimple Interest = \frac{P\times R\times T}{100} 100P×R×T

Solution:Here, Principal (P) = Rs. 56,000, Simple Interest (S.I.) = Rs. 280, Time (T) = 2 yearsSimple Interest = \frac{P\times R\times T}{100} 100P×R×T

Solution:Here, Principal (P) = Rs. 56,000, Simple Interest (S.I.) = Rs. 280, Time (T) = 2 yearsSimple Interest = \frac{P\times R\times T}{100} 100P×R×T

Solution:Here, Principal (P) = Rs. 56,000, Simple Interest (S.I.) = Rs. 280, Time (T) = 2 yearsSimple Interest = \frac{P\times R\times T}{100} 100P×R×T \Rightarrow\ 280=\frac{56000\times R\times2}{100} R=\frac{280\times100}{56000\times2}⇒ 280=

Solution:Here, Principal (P) = Rs. 56,000, Simple Interest (S.I.) = Rs. 280, Time (T) = 2 yearsSimple Interest = \frac{P\times R\times T}{100} 100P×R×T \Rightarrow\ 280=\frac{56000\times R\times2}{100} R=\frac{280\times100}{56000\times2}⇒ 280= 100

Solution:Here, Principal (P) = Rs. 56,000, Simple Interest (S.I.) = Rs. 280, Time (T) = 2 yearsSimple Interest = \frac{P\times R\times T}{100} 100P×R×T \Rightarrow\ 280=\frac{56000\times R\times2}{100} R=\frac{280\times100}{56000\times2}⇒ 280= 10056000×R×2

Solution:Here, Principal (P) = Rs. 56,000, Simple Interest (S.I.) = Rs. 280, Time (T) = 2 yearsSimple Interest = \frac{P\times R\times T}{100} 100P×R×T \Rightarrow\ 280=\frac{56000\times R\times2}{100} R=\frac{280\times100}{56000\times2}⇒ 280= 10056000×R×2

Solution:Here, Principal (P) = Rs. 56,000, Simple Interest (S.I.) = Rs. 280, Time (T) = 2 yearsSimple Interest = \frac{P\times R\times T}{100} 100P×R×T \Rightarrow\ 280=\frac{56000\times R\times2}{100} R=\frac{280\times100}{56000\times2}⇒ 280= 10056000×R×2 ⇒R=

Solution:Here, Principal (P) = Rs. 56,000, Simple Interest (S.I.) = Rs. 280, Time (T) = 2 yearsSimple Interest = \frac{P\times R\times T}{100} 100P×R×T \Rightarrow\ 280=\frac{56000\times R\times2}{100} R=\frac{280\times100}{56000\times2}⇒ 280= 10056000×R×2 ⇒R= 56000×2

Solution:Here, Principal (P) = Rs. 56,000, Simple Interest (S.I.) = Rs. 280, Time (T) = 2 yearsSimple Interest = \frac{P\times R\times T}{100} 100P×R×T \Rightarrow\ 280=\frac{56000\times R\times2}{100} R=\frac{280\times100}{56000\times2}⇒ 280= 10056000×R×2 ⇒R= 56000×2280×100

Solution:Here, Principal (P) = Rs. 56,000, Simple Interest (S.I.) = Rs. 280, Time (T) = 2 yearsSimple Interest = \frac{P\times R\times T}{100} 100P×R×T \Rightarrow\ 280=\frac{56000\times R\times2}{100} R=\frac{280\times100}{56000\times2}⇒ 280= 10056000×R×2 ⇒R= 56000×2280×100

Solution:Here, Principal (P) = Rs. 56,000, Simple Interest (S.I.) = Rs. 280, Time (T) = 2 yearsSimple Interest = \frac{P\times R\times T}{100} 100P×R×T \Rightarrow\ 280=\frac{56000\times R\times2}{100} R=\frac{280\times100}{56000\times2}⇒ 280= 10056000×R×2 ⇒R= 56000×2280×100

Solution:Here, Principal (P) = Rs. 56,000, Simple Interest (S.I.) = Rs. 280, Time (T) = 2 yearsSimple Interest = \frac{P\times R\times T}{100} 100P×R×T \Rightarrow\ 280=\frac{56000\times R\times2}{100} R=\frac{280\times100}{56000\times2}⇒ 280= 10056000×R×2 ⇒R= 56000×2280×100 R\ =\ 0.25\%⇒ R = 0.25%

Solution:Here, Principal (P) = Rs. 56,000, Simple Interest (S.I.) = Rs. 280, Time (T) = 2 yearsSimple Interest = \frac{P\times R\times T}{100} 100P×R×T \Rightarrow\ 280=\frac{56000\times R\times2}{100} R=\frac{280\times100}{56000\times2}⇒ 280= 10056000×R×2 ⇒R= 56000×2280×100 R\ =\ 0.25\%⇒ R = 0.25%Hence, the rate of interest on sum is 0.25%.