What resistance must be added in series to a circuit containing a 33ohm resistor in order to draw 2.0 A of current from a 120V source?
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LET "R" BE THE UNKNOWN RESISTANCE TO BE ADDED IN SERIES
THEN TOTAL RESISTANCE WILL BE (33+R)
.
.
V=IR
120 = 2 × (33+R)
60 = 33+R
R = 60-33
R = 27 OHM
THEN TOTAL RESISTANCE WILL BE (33+R)
.
.
V=IR
120 = 2 × (33+R)
60 = 33+R
R = 60-33
R = 27 OHM
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