Question

what's the ans for this quest

Answer 1

3j is the answer
make me a brainalist please

Answer 2

For the rod moment of inertia at the end of the rod is I=mlsquare/3
$i = 1 \div 2 \times 1 {}^{2} \div 3$
Therefore,moment of inertia is 1/6
Energy =1/2 ×momemt of inertia×angular velocity square
Energy=1/2×1/6×6×6
Energy=3