Question

What's the answer????​

Answer 1

Answer:

• Let the Cat with Odd Sign and Two Hands be a.
• Let Cat Face be b.
• Let Two Hands be c.

☯ According to the Question :

⋆ First Case :

⇢ Cat + Cat + Cat = 30

⇢ a + a + a = 30

⇢ 3a = 30

• Dividing both term by 3

⇢ a = 10

⋆ Second Case :

⇴ Cat + Face + Face = 20

⇴ a + b + b = 20

⇴ 10 + 2b = 20

⇴ 2b = 20 – 10

⇴ 2b = 10

• Dividing both term by 2

⇴ b = 5

⋆ Third Case :

⇢ Face + 2Hands + 2Hands = 9

⇢ b + c + c = 9

⇢ 5 + 2c = 9

⇢ 2c = 9 – 5

⇢ 2c = 4

• Dividing both term by 2

⇢ c = 2

• If Value of Two Hands = 2, then Value of One Hand will be = 1.

⋆ Fourth Case :

⇴ Cat without 1Hand × 1Hand + Face

⇴ (Cat – 1Hand) × 1Hand + Face

⇴ (a – 1) × 1 + b

⇴ (10 – 1) × 1 + 5

⇴ 9 × 1 + 5

⇴ 9 + 5

⇴ 14

∴ Therefore, Required value will be 14.

Answer 2

hello... ☺☺

3 cats = 30

1cat =10

let the only face of cat = 5

and one hand of cat =1

the cat not have the right hand whose value is 1 =10-1 =9

Therefore.. 9×1+5=14

take care..... ☺☺☺