Question

what's the answer for this.. kindly help me with this​

Answer 1

Step-by-step explanation:

Given,

$\frac{{1 - \sqrt{3} } }{1 + \sqrt{3} } = a + b$

Rationalizing the denominator in lhs,

$= > \frac{(1 - \sqrt{3} )(1 - \sqrt{3} )}{(1 + \sqrt{3} )(1 - \sqrt{3} )} = a + b$

$= > \frac{ {(1 - \sqrt{3}) }^{2} }{1 - 3} = a + b$

$= > \frac{1 + 3 - 2 \sqrt{3} }{ - 2} = a + b$

$= > \frac{ - 2( \sqrt{3} - 2) }{ - 2} = a + b$

$= > \sqrt{3} + ( - 2) = a + b \: \: or \: \: ( - 2) + \sqrt{3} = a + b$

Hence either a=√3 and b=(-2) or a=(-2) and b=√3