Chemistry, asked by PBU, 11 months ago

what's the answer of this question ​

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Answered by aryan12326
1

Answer:

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E₁ = - 2.18 × 10⁻¹¹ ergs

En = E₁ / n²

E₅ = (-2.18 × 10⁻¹¹) / 5²

E₅ = (-2.18 × 10⁻¹¹) / 25 = - 8.72 × 10⁻¹³

ΔE = E₅ - E₁

= - 8.72 × 10⁻¹³ - (- 2.18 × 10⁻¹¹) = 2.09828 × 10⁻¹¹ ergs.

1 ergs = 10⁻⁷ joules

Converting in joules :

2.09828 × 10⁻¹¹ × 10⁻⁷ = 2.09828 × 10⁻¹⁸ Joules

ΔE = hc/y

Y = wavelength

h = planks constant = 6.62 × 10⁻³⁴

c = speed of light = 3.0 × 10⁸

Doing the substitution we have :

2.09828 × 10⁻¹¹ = (6.62 × 10⁻³⁴ × 3 × 10⁸) / Y

Y = (6.62 × 10⁻³⁴ × 3 × 10⁸) / (2.09828 × 10⁻¹¹) = 9.465 × 10⁻¹⁵ cm

= 9.465 × 10⁻¹⁵ cm

Answered by vedavidyasvy
1

Answer:

which class question is it'

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