What’s the answer to the final equation?
1- T x T = 16
2- T x C x C = 36
3- T x C x K = 72
(yes, plus)
4- T + C + K = ???
Answers
Answered by
5
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
1. T x T = 16
MEANS T = 4
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
2. T x C x C = 36
4 x C X C = 36
C x C = 36/4
C X C = 9
MEANS C = 3 .........SINCE 3^2= 9
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
T X C X K = 72
4 X 3 X K = 72
12K = 72
K = 72/12
K = 6
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
NOW,
T + C + K
4 + 3 + 6
13
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
1. T x T = 16
MEANS T = 4
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
2. T x C x C = 36
4 x C X C = 36
C x C = 36/4
C X C = 9
MEANS C = 3 .........SINCE 3^2= 9
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
T X C X K = 72
4 X 3 X K = 72
12K = 72
K = 72/12
K = 6
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
NOW,
T + C + K
4 + 3 + 6
13
⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕⭕
shreya32457:
tnx...
Answered by
9
T× T = 16
T^2 = 16
T = 4
putting T = 4 in 2nd eq
T× C × C = 36
4 × C ^2 = 36
C^2 = 36/4
C^2 = 9
C = 3
putting T = 4 and C = 3 in eq 3
T × C × K = 72
4 × 3 × K = 72
K = 72/12
K = 6
now putting T = 4 , C = 3 and K = 6 in eq 4
T + C + K = 4 +3 + 6
= 13
=> the ans is 13 ...
hope this will help uh ....
nd plzz mark as brainliest ...
T^2 = 16
T = 4
putting T = 4 in 2nd eq
T× C × C = 36
4 × C ^2 = 36
C^2 = 36/4
C^2 = 9
C = 3
putting T = 4 and C = 3 in eq 3
T × C × K = 72
4 × 3 × K = 72
K = 72/12
K = 6
now putting T = 4 , C = 3 and K = 6 in eq 4
T + C + K = 4 +3 + 6
= 13
=> the ans is 13 ...
hope this will help uh ....
nd plzz mark as brainliest ...
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