Question

What's the area in sq.Cm. Of the triangle with a base of 8 cm and sides of length 6cm each?

Answer 1

Answer:

(4.47 * 8)/2 = 17.88                     ( answer is approximate )

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Answer 2

Answer:

8√5 sq. cm

Step-by-step explanation:

draw a perpendicular to base

the two triangles so formed are ABD & ACD

            AD = AD    (COMMON)

        ANGLE ADB = ANGLE ADC = 90       ( CONSTRUCTION)

              AB = AC = 6               (GIVEN)

∴ ABD≅ACD                              (RHS CONGRUENCE RULE)

⇒ BD = CD        (C.P.C.T.E.)

BC = 8

BD = 0.5 * 8

= 4

USING PYTHAGORAS THEOREM

AB^2 = BD^2 + AD^2

6^2 = 4^2 + AD^2

AD^2 = 36-16

AD^2 = 20

AD = 2√5

AREA OF TRIANGLE = 0.5 * BASE * HEIGHT

= 0.5 * 8 * 2√5

= 4 * 2√5

= 8√5 sq. cm

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