Math, asked by YASH3100, 10 months ago

WHAT'S THE DIFFERENTIAL OF 2^x

Answers

Answered by smartyrathore
4

Hey Guys Here is your answer

y=2^x

log^y=X.log^2

d.w.r t.x

1/y.dy/dx=x.0+log^2

dy/dx=y.log^2

✍️✍️ please mark it brainlist answer...


Anonymous: here, I am unable to type answer
Anonymous: @logy
smartyrathore: ohhh no problem Will learn
smartyrathore: please mark it brainlist answer...
Anonymous: equals to @xlog2
smartyrathore: no
Anonymous: now differentiate
Anonymous: by product rule
smartyrathore: thanks
Anonymous: you were forgot to put the value of y... xd
Answered by brunoconti
0

Answer:

Step-by-step explanation:

BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST BRAINLIEST

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