Question

what's the distance between (0, 0) (36, 15) {coordinate geometry}​

Answer 1

Step-by-step explanation:

Given:-

two points (0, 0) and (36, 15)

To find:-

Find the distance between the two points

(0, 0) and (36, 15)

Solution:-

Method-1:-

Given points are (0, 0) and (36, 15)

We know that

The distance between the Origin and the point A(x,y) is √[x^2+y^2] units

Let (x, y)=(36,15)=>x = 36 and y= 15

The distance = √[(36)^2+(15)^2] units

=>√(1296+225) units

=>√1521 units

=>39 units

Method-2:-

Let (x1, y1)=(0,0)=>x1=0 and y1=0

Let (x2, y2)=(36,15)=>x2=36 and y2=15

We know that

The distance between the two points (x1, y1) and (x2, y2) is √[(x2-x1)^2+(y2-y1)^2] units

On Substituting these values in the above formula

=>√[(36-0)^2+(15-0)^2] units

=>√[(36)^2+(15)^2] units

=>√(1296+225) units

=>√1521 units

=>39 units

Answer:-

The required distance between two points is

39 units

Used formulae:-

• The distance between the Origin and the point A(x,y) is √[x^2+y^2] units
• The distance between the two points (x1, y1) and (x2, y2) is √[(x2-x1)^2+(y2-y1)^2] units

Answer 2

Answer:

39

Step-by-step explanation:

We know that dist. formula =✓(x2-x1)²+(y2-y1)²

Here, X2=36 ,X1=0

Y2=15 ,Y1=0

Therefore dist. between them is given by-

✓(36-0)² + (15-0)²

=✓ 36² + 15²

=✓1296+225

= ✓1521

=39.

Hope it helped!!!