Question

What's the equivalent weight of ferrous oxalate

Answer 1

The Equivalent weight of Ferrous oxalate in general case is its molecular weight divided by 2(n-factor).

Equivalent weight = 144/2 = 72

Answer 2

Answer: Equivalent weight of $FeC_2O_4$ is 72 g/eq.

Explanation: First we calculate the molar mass of $FeC_2O_4$

Molar mass of $FeC_2O_4$ = 56 + (2 × 12) + (4 × 16) = 144 g

As, this compound is a salt, so the equivalent mass of the salt is equal to the molar mass divided by the total valency of the metal in that salt.

$\text{Equivalent weight}=\frac{\text{Molar mass}}{\text{Valency of Metal}}$

Valency of metal ( Fe) in the salt = 2

Hence,

$\text{Equivalent weight}=\frac{144}{2}=72 g/eq$

Therefore, equivalent weight of $FeC_2O_4$ is 72 g/eq.