Question

What’s the kinetic energy of the roller coaster at the top and bottom of the hill?
Use KE=1/2mv^2 A kiddie roller coaster car has a mass 100 kilograms. At the top of a hill, it’s moving at a speed of 3 meters/second. After reaching the bottom of the hill, its speed doubles. The car’s kinetic energy at the bottom is (half, double, triple or quadruple) its kinetic energy at the top. The car has (450, 900, 1,800, 3,600) joules of kinetic energy at the bottom of the hill.

Answer 1

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Answer 2

Given that,

Mass of the car, m = 100 kg

At the top of the hill, it is moving at a speed of 3 m/s, v = 3 m/s

To find,

The kinetic energy of the roller coaster at the top and bottom of the hill.

Solution,

Kinetic energy will be possessed by an object when it is moving with some velocity. It is given by :

$K=\dfrac{1}{2}mv^2\\\\K=\dfrac{1}{2}\times 100\times (3)^2\\\\K=450\ J$

After reaching the bottom of the hill, its speed doubles. Kinetic energy is directly proportional to the speed of an object. So, if speed doubles, its kinetic energy will also gets double.

Initial the kinetic energy is 450 J. On doubling speed,

v = 2v

New kinetic energy :

$K=\dfrac{1}{2}mv^2\\\\K=\dfrac{1}{2}\times 100\times (6)^2\\\\K=1800\ J$

Learn more,

Kinetic energy

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