What's the length of side AB in ΔABC shown?
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Answered by
4
Answer:
5
Step-by-step explanation:
You are to use Pythagoras' Theorem here since it is a right angled triangle (the right angle is marked at vertex A).
By the Pythagoras' Theorem, we must have
x² + 12² = 13²
So
x² = 13² - 12² = 169 - 144 = 25
From here, you get x = 5.
Answered by
3
Hello friend
here is your answer
BC^2 = AB^2 + AC^2
or,. AB^2 = BC^2 - AB^2
or, AB. = √BC^2 - AB^2
or, AB = √(13)^2 - (12)^2
or, AB = √169 - 144
or, AB = √25 = 5
the value of AB is 5
hope it helps
here is your answer
BC^2 = AB^2 + AC^2
or,. AB^2 = BC^2 - AB^2
or, AB. = √BC^2 - AB^2
or, AB = √(13)^2 - (12)^2
or, AB = √169 - 144
or, AB = √25 = 5
the value of AB is 5
hope it helps
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