Question

what's the order of rusting of iron?​

Answer 1

Answer:

iron is kept exposed to air and when moisture and oxygen reacts with iron rust is formed on it

Answer 2

Answer:

It occurs in moist air and in water. Rust requires three chemicals in order to form: iron, oxygen, and water. Because of the electrochemical nature of the reaction, dissolved electrolytes in water aid the reaction. Rust occurs more quickly in saltwater than in pure water....

• Rust is the common name of the chemical called iron oxide. Technically, it's iron oxide hydrate, because pure iron oxide isn't rust.
• Rust forms when iron or its alloys are exposed to moist air. The oxygen and water in air react with the metal to form the hydrated oxide.
• The familiar red form of rust is (Fe2O3), but iron has other oxidation states, so it can form other colors of rust.

How Rust Works

• Rust is the common name of the chemical called iron oxide. Technically, it's iron oxide hydrate, because pure iron oxide isn't rust.
• Rust forms when iron or its alloys are exposed to moist air. The oxygen and water in air react with the metal to form the hydrated oxide.
• The familiar red form of rust is (Fe2O3), but iron has other oxidation states, so it can form other colors of rust.

The Chemical Reaction That Forms Rust. Although rust is considered the result of an oxidation reaction, it's worth noting not all iron oxides are rust. Rust forms when oxygen reacts with iron, but simply putting iron and oxygen together isn't sufficient. Although about 21% of air consists of oxygen,1 rusting doesn't occur in dry air. It occurs in moist air and in water. Rust requires three chemicals in order to form: iron, oxygen, and water.

iron + water + oxygen → hydrated iron(III) oxide

This is an example of an electrochemical reaction and corrosion. Two distinct electrochemical reactions occur:

There is anodic dissolution or oxidation of iron going into aqueous (water) solution:

2Fe → 2Fe2+ + 4e-

Cathodic reduction of oxygen that is dissolved into water also occurs:

O2 + 2H2O + 4e- → 4OH-

The iron ion and the hydroxide ion react to form iron hydroxide:

2Fe2+ + 4OH- → 2Fe(OH)2

The iron oxide reacts with oxygen to yield red rust, Fe2O3.H2O