What's the REMINDER when 2^(123456789) is DIVISIBLE by 7?
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Answers
Answered by
1
2^129456789 can be written as
(2^3)^43152263.
= (7+1)^43152263
By using remander theorem..we have result as
7*k + 1^43152263.
hence remainder is 1.
Answered by
2
Answer:
Step-by-step explanation:
First method
41152263*3=123456789 and (2^3) / 7 = 1 (remainder) , hence we have the remainder as 1
+1
Ans is 1.
Second method
2^129456789 can be written as (2^3)^43152263.
= (7+1)^43152263
By expanding the above expression...we get the result as 7*k + 1^43152263.
So the remainder is 1.
Hope it helps u
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