Question

what's the slop of T² vs 1 graph?​

Answer 1

Answer:

The length of the pendulum L is directly proportional to the square of its period T^2 and is inversely proportional to the acceleration due to gravity g. The equation is T^2 = 4 * pi^2 * L/g. Manipulating the formula gives L/T^2 = g / (4 * pi^2) . This suggest that the slope of the straight line L/T^2 is equal to the quotient of g and (4 * pi^2). You do not need to make a graph to determine the slope of the straight line. Just evaluate the expression g / (4 * pi^2). If g = 9.8 m/s^2 and pi = 3.1415626 then

slope = g / (4 * pi^2)

slope = 9.8 m/s^2 /(4 * (3.1415626)^2

slope = 9.8 m/s^2 / (4 * 9.8696041)

slope = 9.8 m/s^2 / 39.478416

slope = 0.2482 m/s