what's the sum of 1 to 100 natural numbers
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Let S be the required sum. Clearly, it is an Arithmetic Progression whose first term = 1, last term = 100 and number of terms = 100. Therefore, the sum of first 100 natural numbers is 5050.
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Sum of the 1 to 100 numbers is
n(n+1)/2
100×(100+1)/2
100 ×101/2
50×101
5050
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