Question

What's the sum of first 48 negative integer [ -1+(-2)+(-3)+(-4)+....+(-48)] ?​

Answer 1

here is your answer mate:

-1 , -2 , -3 ........ -48

a = -1 ; d = -1 ; l = 48

Sum =  n/2 (a + l)

= 48/2 (-1 + (-48))

= 24 x -49

-1176

hope it helps you buddy

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Answer 2

Answer:

-1476

Step-by-step explanation:

add it normaly and put the negative mark next to it

please make sure you mark as brainliest if helpful