what's the value of (a+b-c)^2 ?
samyak201:
yes
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1
(a+b-c) ^2
= (a) ^2 +(b) ^2 +(-c) ^2 +2(a)(b) + 2(b)(-c) + 2(-c)(a)
= a^2 +b^2 +c^2 +2ab - 2bc - 2ca
= (a) ^2 +(b) ^2 +(-c) ^2 +2(a)(b) + 2(b)(-c) + 2(-c)(a)
= a^2 +b^2 +c^2 +2ab - 2bc - 2ca
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(a+b+c)2 = a2 + b2 + c2 +2ab -2bc -2ca
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