Question

What's the value of x, in the equation below?
$\sqrt{ 2 \sqrt{ 2 \sqrt{ 2 \sqrt{ 2 \sqrt{ 2 \sqrt{ 2 \sqrt{ 2 } } } } } } } \div (2 ^ { 127 } ) ^ { \frac{ 1 }{ 128 } } =2 ^ { x }$
​

Answer 1

Answer:

=3^x×3^3=9

=3^x+3=3^2

=x+3=2

=x= -1