Question

What’s the velocity of the balloon? Use v=$\sqrt2ke/m$
A hot-air balloon with a mass of 400 kilograms moves across the sky with 3,200 joules of kinetic energy

Answer 1

Answer:

V=$\sqrt{x}$2ke/m

$\sqrt{x}$2x3,200/400=16m/s

Explanation:

Answer 2

Velocity of the balloon = 4m/sec

Kinetic energy is an energy that is possesses due to the motion of the object.

.) Mathematically kinetic energy can be written as :

KE = ½*m*v^2

Where KE is kinetic energy , m is the mass of the object and v is the velocity of the object .

.) According to the question ,

KE = 3200J , m = 400kg

.) Now putting the values in the equation and solving it we get ,

3200 = ½ * 400*v^2

=> v^2 = 3200 * 2 / 400

=> v^2 = 6400/400

=> v^2 = 16

=> v = √16

=> v = ± 4m/sec

=> v = 4m/sec